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  4. In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm . Choose the closest value of change in the stopping potential from given options ((h c/e) = 1240 nm ⋅ V)

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Q. In a photoelectric experiment, the wavelength of the light incident on a metal is changed from $300nm$ to $400nm$ . Choose the closest value of change in the stopping potential from given options $\left(\frac{h c}{e} = 1240 nm \cdot V\right)$

NTA AbhyasNTA Abhyas 2022

Solution:

$v_{s_{1}}=\frac{1240}{300}-\phi$
$v_{s_{2}}=\frac{1240}{400}-\phi$
$v_{s_{1}}-v_{s_{2}}=\frac{1240}{300}-\frac{1240}{400}$
$=4.13-3.1$
$=1.03$
$=1$