Q. In a non leap year the probability of getting 53 Sundays or 53 Tuesdays or 53 Thursdays

1559 234 Probability - Part 2 Report Error

A

$\frac{1}{7}$

100%

B

$\frac{2}{7}$

0%

C

$\frac{3}{7}$

0%

D

$\frac{4}{7}$

0%

Solution:

$P (A) = \frac{3}{7}$