In a metallic triangular sheet ABC , AB = BC = l . If M is mass of sheet, what is the moment of inertia about AC ?

Question

In a metallic triangular sheet ABC , AB = BC = l . If M is mass of sheet, what is the moment of inertia about AC ? (A)  (Ml2/4)  (B)  (Ml2/12)  (C)  (Ml2/6)  (D)  (Ml2/18)

Tardigrade Admin · Accepted Answer

Moment of inertia of triangular sheet A B C about A C=(1/2) moment of inertia of square A B C D about A C <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/91eeef82af00142b8433cdfee0aafea5-.png" /> =(1/2)(2 M) (l2/12)=(M l2/12)

Q. In a metallic triangular sheet $A BC$ , $A B = BC = l$ . If $M$ is mass of sheet, what is the moment of inertia about $A C$ ?

$\frac{M l ^{2}}{4}$

$\frac{M l ^{2}}{12}$

$\frac{M l ^{2}}{6}$

$\frac{M l ^{2}}{18}$

Moment of inertia of triangular sheet $A BC$ about $A C = \frac{1}{2}$ moment of inertia of square $A BC D$ about $A C$

$= \frac{1}{2} (2 M) \frac{l ^{2}}{12} = \frac{M l ^{2}}{12}$

Q. In a metallic triangular sheet ABC , AB=BC=l . If M is mass of sheet, what is the moment of inertia about AC ?

4Ml2​

12Ml2​

6Ml2​

18Ml2​