In a magnetic field of 0.05 T, area of a coil changes from 101 cm2 to 100 cm2 without changing the resistance which is 2 Ω. The amount of charge that flow during this period is

Question

In a magnetic field of 0.05 T, area of a coil changes from 101 cm2 to 100 cm2 without changing the resistance which is 2 Ω. The amount of charge that flow during this period is (A) 2.5 × 10-6 C (B) 2 × 10-6 C (C) 10-6 C (D) 8 × 10-6 C

Tardigrade Admin · Accepted Answer

Magnetic Flux, φ=B⋅ A Change in flux, d φ=B⋅ dA =0.05(101-100)×10-4 =5×10-6 Wb Charge dQ=(dφ/R) =(5×10-6/2)=2.5×10-6 C

Q. In a magnetic field of $0.05 T,$ area of a coil changes from $101 c m^{2}$ to $100 c m^{2}$ without changing the resistance which is $2 Ω$ . The amount of charge that flow during this period is

$2.5 \times 1 0^{- 6} C$

$2 \times 1 0^{- 6} C$

$1 0^{- 6} C$

$8 \times 1 0^{- 6} C$

Magnetic Flux, $ϕ = B \cdot A$
Change in flux, $d ϕ = B \cdot d A$
$= 0.05 (101 - 100) \times 1 0^{- 4}$
$= 5 \times 1 0^{- 6} Wb$
Charge $d Q = \frac{d ϕ}{R}$
$= \frac{5 \times 1 0 ^{- 6}}{2} = 2.5 \times 1 0^{- 6} C$

Q. In a magnetic field of 0.05T, area of a coil changes from 101cm2 to 100cm2 without changing the resistance which is 2Ω. The amount of charge that flow during this period is

2.5×10−6C

2×10−6C

10−6C

8×10−6C