Question

For the circuit shown below, calculate the value of $I_z$ :

• A. 25 mA
• B. 0.15 A
• C. 0.1 A
• D. 0.05 A

Answer 1

Answer: (A)

$I=\frac{50}{1000}=50mA$

$I=\frac{50}{2000}=25mA$
$I_Z=I_{1000}-I_{2000}$
$=50-25=25mA$