In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70 m, then the minimum height of the transmitting antenna should be: (Radius of the Earth = 6.4 × 106 m).

Question

In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70 m, then the minimum height of the transmitting antenna should be: (Radius of the Earth = 6.4 × 106 m). (A) 40 m (B) 51 m (C) 32 m (D) 20 m

Tardigrade Admin · Accepted Answer

Range = √2RhT + √2RhR 50 × 103 = √2 ×6400 × 103× hT + √2 ×6400 ×103 ×70 by solving hT = 32 m

Q. In a line of sight radio communication, a distance of about $50 km$ is kept between the transmitting and receiving antennas. If the height of the receiving antenna is $70 m$ , then the minimum height of the transmitting antenna should be :
(Radius of the Earth = $6.4 \times 1 0^{6} m$ ).

40 m

51 m

32 m

20 m

Range = $2 R h_{T} + 2 R h_{R}$
$50 \times 1 0^{3} = 2 \times 6400 \times 1 0^{3} \times h_{T} + 2 \times 6400 \times 1 0^{3} \times 70$
by solving $h_{T} = 32 m$

Q. In a line of sight radio communication, a distance of about 50km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70m, then the minimum height of the transmitting antenna should be : (Radius of the Earth = 6.4×106m).