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  4. In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70 m, then the minimum height of the transmitting antenna should be: (Radius of the Earth = 6.4 × 106 m).

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Q. In a line of sight radio communication, a distance of about $50\, km$ is kept between the transmitting and receiving antennas. If the height of the receiving antenna is $70\,m$, then the minimum height of the transmitting antenna should be :
(Radius of the Earth = $6.4 \times 10^6 m$).

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Solution:

Range = $\sqrt{2Rh_{T}} + \sqrt{2Rh_{R}} $
$50 \times 10^{3} = \sqrt{2 \times6400 \times 10^{3}\times h_{T}} + \sqrt{2 \times6400 \times10^{3} \times70} $
by solving $h_T = 32\, m$