In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If m n, then m =

Question

In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If m > n, then m = (A) 6 (B) 7 (C) 8 (D) 9

Tardigrade Admin · Accepted Answer

2 ⋅ m ! ⋅ n !=1209600 ⇒ m ! n !=604800=(7 !)(5 !) ⇒ m =7

Q. In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If $m > n$ , then $m =$

6

7

8

9

$2 \cdot m! \cdot n! = 1209600 \Rightarrow m! n! = 604800 = (7!) (5!) \Rightarrow m = 7$

Q. In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If m>n, then m=

6

7

8

9

2⋅m!⋅n!=1209600⇒m!n!=604800=(7!)(5!)⇒m=7

Q. In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If $m > n$ , then $m =$

$2 \cdot m! \cdot n! = 1209600 \Rightarrow m! n! = 604800 = (7!) (5!) \Rightarrow m = 7$