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Q. In a library there are m different books of mathematics and n different books of natural science. They can be placed on a shelf in 1209600 ways so that books of the same subject are not seperated. If $m > n$, then $m =$

Permutations and Combinations

Solution:

$2 \cdot m ! \cdot n !=1209600 \Rightarrow m ! n !=604800=(7 !)(5 !) \Rightarrow m =7$