In a leap year the probability of having 53 Sundays or 53 Mondays is

Question

In a leap year the probability of having 53 Sundays or 53 Mondays is (A) (2/7) (B) (3/7) (C) (4/7) (D) (5/7)

Tardigrade Admin · Accepted Answer

Since a leap year has 366 days and hence 52 weeks and 2 days. The 2 days can be SM, MT, TW, WTh, ThF, FSt, St.S. Therefore, P(53 Sundays or 53 Mondays) = (3/7)

Q. In a leap year the probability of having 53 Sundays or 53 Mondays is

$\frac{2}{7}$

$\frac{3}{7}$

$\frac{4}{7}$

$\frac{5}{7}$

Since a leap year has 366 days and hence 52 weeks and 2 days. The 2 days can be SM, MT, TW, WTh, ThF, FSt, St.S.
Therefore, P(53 Sundays or 53 Mondays) $= \frac{3}{7}$