In a LCR series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that across the resistance is 40 V. Then, supply voltage will be equal to

Question

In a LCR series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that across the resistance is 40 V. Then, supply voltage will be equal to (A) 50V (B) 70V (C) 130V (D) 10 V

Tardigrade Admin · Accepted Answer

In LCR series circuit, V=√VR2+(VL-VC)2 =√(40)2+(60-30)2 =√1600+900=√2500 =50 text V

Q. In a LCR series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that across the resistance is 40 V. Then, supply voltage will be equal to

50V

70V

130V

10 V

In LCR series circuit, $V = V_{R}^{2} + (V_{L} - V_{C})^{2}$ $= (40)^{2} + (60 - 30)^{2}$ $= 1600 + 900 = 2500$ $= 50 V$

Q. In a LCR series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that across the resistance is 40 V. Then, supply voltage will be equal to

50V

70V

130V

10 V

In LCR series circuit, V=VR2​+(VL​−VC​)2​ =(40)2+(60−30)2​ =1600+900​=2500​ =50V

In LCR series circuit, $V = V_{R}^{2} + (V_{L} - V_{C})^{2}$ $= (40)^{2} + (60 - 30)^{2}$ $= 1600 + 900 = 2500$ $= 50 V$