In a LC circuit, angular frequency at resonance is ω. What will be the new angular frequency when inductor's inductance is made 2 times and capacitance is made 4 times?

Question

In a LC circuit, angular frequency at resonance is ω. What will be the new angular frequency when inductor's inductance is made 2 times and capacitance is made 4 times? (A) ( /√2) (B) ( /2√2) (C) 2 ω (D) (2/√2)

Tardigrade Admin · Accepted Answer

=(1/√LC) Now if L' = 2L, C' = 4C '=(1/√2L⋅4C) '=(1/2√2). (1/√LC)=( /2√2)

Q. In a LC circuit, angular frequency at resonance is $ω$ . What will be the new angular frequency when inductor's inductance is made $2$ times and capacitance is made $4$ times?

$2$

$2 2$

$2 ω$

$\frac{2}{2}$

$= \frac{1}{L C}$
Now if L' = 2L, C' = 4C
$^{'} = \frac{1}{2 L \cdot 4 C}$
$^{'} = \frac{1}{2 2} . \frac{1}{L C} = 2 2$

Q. In a LC circuit, angular frequency at resonance is ω. What will be the new angular frequency when inductor's inductance is made 2 times and capacitance is made 4 times?

2​​

22​​

2ω

2​2​

=LC​1​ Now if L' = 2L, C' = 4C ′=2L⋅4C​1​ ′=22​1​.LC​1​=22​​

Q. In a LC circuit, angular frequency at resonance is $ω$ . What will be the new angular frequency when inductor's inductance is made $2$ times and capacitance is made $4$ times?

$2$

$2 2$

$2 ω$

$\frac{2}{2}$

$= \frac{1}{L C}$
Now if L' = 2L, C' = 4C
$^{'} = \frac{1}{2 L \cdot 4 C}$
$^{'} = \frac{1}{2 2} . \frac{1}{L C} = 2 2$