In a hydrogen atom, an electron of mass m and charge e revolves in an orbit of radius r making n revolutions per second. If the mass of hydrogen nucleus is M, the magnetic moment associated with the orbital motion of electron is

Question

In a hydrogen atom, an electron of mass m and charge e revolves in an orbit of radius r making n revolutions per second. If the mass of hydrogen nucleus is M, the magnetic moment associated with the orbital motion of electron is (A) (π n e r2 m/M+m) (B) π n e r2 (C) (π n e r2/m) (D) (π n e r2 m/M)

Tardigrade Admin · Accepted Answer

Magnetic moment = NiA i=(q/T)=e n A=π r2 and N=1 ⇒ Magnetic moment (m)=(1)(e n)(π r2)

Q. In a hydrogen atom, an electron of mass $m$ and charge e revolves in an orbit of radius $r$ making $n$ revolutions per second. If the mass of hydrogen nucleus is $M$ , the magnetic moment associated with the orbital motion of electron is

$\frac{πn e r ^{2} m}{M + m}$

$πn e r^{2}$

$\frac{πn e r ^{2}}{m}$

$\frac{πn e r ^{2} m}{M}$

Magnetic moment $= N i A$
$i = \frac{q}{T} = e n$
$A = π r^{2}$
and $N = 1$
$\Rightarrow$ Magnetic moment
$(m) = (1) (e n) (π r^{2})$

Q. In a hydrogen atom, an electron of mass m and charge e revolves in an orbit of radius r making n revolutions per second. If the mass of hydrogen nucleus is M, the magnetic moment associated with the orbital motion of electron is

M+mπner2m​

πner2

mπner2​

Mπner2m​