In a hydrogen atom, an electron moves in an orbit of radius 5.0 × 10-11 m with a speed of 2.2 × 106 ms -1. The equivalent current is

Question

In a hydrogen atom, an electron moves in an orbit of radius 5.0 × 10-11 m with a speed of 2.2 × 106 ms -1. The equivalent current is (A) 11.2 × 10-3 A (B) 1.9 × 10-3 A (C) 1.12 × 10-3 A (D) 11.2 × 104 A

Tardigrade Admin · Accepted Answer

Time period of revolution, T =(2 π r/v) =(2 × 3.14 ×(5.0 × 10-11 m )/2.2 × 106 ms -1) =14.27 × 10-17 s Equivalent current =( Charge / text Time )=(e/T)=(1.6 × 10-19 C /14.27 × 10-17 s ) =0.112 × 10-2 A =1.12 × 10-3 A

Q. In a hydrogen atom, an electron moves in an orbit of radius $5.0 \times 1 0^{- 11} m$ with a speed of $2.2 \times 1 0^{6} m s^{- 1}$ . The equivalent current is

$11.2 \times 1 0^{- 3} A$

$1.9 \times 1 0^{- 3} A$

$1.12 \times 1 0^{- 3} A$

$11.2 \times 1 0^{4} A$

Q. In a hydrogen atom, an electron moves in an orbit of radius 5.0×10−11m with a speed of 2.2×106ms−1. The equivalent current is

11.2×10−3A

1.9×10−3A

1.12×10−3A

11.2×104A

Timeperiodofrevolution,T=v2πr​ =2.2×106ms−12×3.14×(5.0×10−11m)​ =14.27×10−17sEquivalentcurrent= Time Charge​=Te​=14.27×10−17s1.6×10−19C​ =0.112×10−2A=1.12×10−3A

Q. In a hydrogen atom, an electron moves in an orbit of radius $5.0 \times 1 0^{- 11} m$ with a speed of $2.2 \times 1 0^{6} m s^{- 1}$ . The equivalent current is

$11.2 \times 1 0^{- 3} A$

$1.9 \times 1 0^{- 3} A$

$1.12 \times 1 0^{- 3} A$

$11.2 \times 1 0^{4} A$