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Q.
In a hydrogen atom, an electron moves in an orbit of radius $5.0 \times 10^{-11} m$ with a speed of $2.2 \times 10^{6} ms ^{-1}$. The equivalent current is
Current Electricity
Solution:
$ { Time period of revolution, } T =\frac{2 \pi r}{v} $
$=\frac{2 \times 3.14 \times\left(5.0 \times 10^{-11} m \right)}{2.2 \times 10^{6} ms ^{-1}} $
$=14.27 \times 10^{-17} s { Equivalent current } =\frac{ { Charge }}{\text { Time }}=\frac{e}{T}=\frac{1.6 \times 10^{-19} C }{14.27 \times 10^{-17} s } $
$=0.112 \times 10^{-2} A =1.12 \times 10^{-3} A$