In a horse race, the odds are 14: 1 against the horse 'A' winning. In another horse race, the odds are 20:1 against the horse ' B ' winning. The chance that none of the two horses win the race is

Question

In a horse race, the odds are 14: 1 against the horse 'A' winning. In another horse race, the odds are 20:1 against the horse ' B ' winning. The chance that none of the two horses win the race is (A) (19/21) (B) (8/9) (C) (41/45) (D) (31/35)

Tardigrade Admin · Accepted Answer

P(A)=(1/15) ; P(B)=(1/21) P ( A text or B )=(1/15)+(1/21)=(7+5/105)=(12/105)=(4/35) P ( text nobody wins )=1-(4/35)=(31/35)

Q. In a horse race, the odds are $14 : 1$ against the horse 'A' winning. In another horse race, the odds are 20:1 against the horse ' $B$ ' winning. The chance that none of the two horses win the race is

$\frac{19}{21}$

$\frac{8}{9}$

$\frac{41}{45}$

$\frac{31}{35}$

$P (A) = \frac{1}{15}; P (B) = \frac{1}{21}$
$P (A or B) = \frac{1}{15} + \frac{1}{21} = \frac{7 + 5}{105} = \frac{12}{105} = \frac{4}{35}$
$P (nobody wins) = 1 - \frac{4}{35} = \frac{31}{35}$

Q. In a horse race, the odds are 14:1 against the horse 'A' winning. In another horse race, the odds are 20:1 against the horse ' B ' winning. The chance that none of the two horses win the race is

2119​

98​

4541​

3531​