In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

Question

In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bcafe58b400aff40fd87d9a6a4d83da9-.png" /> In shell, q charge is uniformly distributed over its surface, it behaves as a conductor. V = potential at surface =( q /4 π ε0 R ) and inside V =( q /4 π ε0 R ) Because of this it behaves as an equipotential surface.

Q. In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

In shell, q charge is uniformly distributed over its surface, it behaves as a conductor.
$V =$ potential at surface $= \frac{q}{4 π ε _{0} R}$ and inside $V = \frac{q}{4 π ε _{0} R}$
Because of this it behaves as an equipotential surface.

Q. In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

In shell, q charge is uniformly distributed over its surface, it behaves as a conductor. V= potential at surface =4πε0​Rq​ and inside V=4πε0​Rq​ Because of this it behaves as an equipotential surface.

In shell, q charge is uniformly distributed over its surface, it behaves as a conductor.
$V =$ potential at surface $= \frac{q}{4 π ε _{0} R}$ and inside $V = \frac{q}{4 π ε _{0} R}$
Because of this it behaves as an equipotential surface.