In a given network the equivalent capacitance between A and B is C 1= C 4=1 μ F , C 2= C 3=2 μ F.

Question

In a given network the equivalent capacitance between A and B is C 1= C 4=1 μ F , C 2= C 3=2 μ F. (A) 3 μ F (B) 6 μ F (C) 4.5 μ F (D) 2.5 μ F

Tardigrade Admin · Accepted Answer

The equivalent circuit is shown in figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a06c94392b1e7324958d6c13b9d7482e-.png" /> C A B =1+(2 × 2/2+2)+1 C A B =3 μ F .

Q. In a given network the equivalent capacitance between $A$ and $B$ is $C_{1} = C_{4} = 1 μ F, C_{2} = C_{3} = 2 μ F$ .

$3 μ F$

$6 μ F$

$4.5 μ F$

$2.5 μ F$

The equivalent circuit is shown in figure.

$C_{A B} = 1 + \frac{2 \times 2}{2 + 2} + 1$
$C_{A B} = 3 μ F .$

Q. In a given network the equivalent capacitance between A and B is C1​=C4​=1μF,C2​=C3​=2μF.

3μF

6μF

4.5μF

2.5μF