In a galvanometer 5 % of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance 5 connected to the galvanometer is

Question

In a galvanometer 5 % of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance 5 connected to the galvanometer is (A) 19 G (B) (G/19) (C) 20 G (D) (G/20)

Tardigrade Admin · Accepted Answer

Let the total passing be I. Thus current passing through galvanometer IG=0.05 I Also, current passing through shunt resistance I s =I-0.05 I=0.95 I Using I5 S=IG G ∴ ( S / G )=(0.05/0.95)=(1/10) ⇒ S =( G /19)

Q. In a galvanometer $5%$ of the total current in the circuit passes through it. If the resistance of the galvanometer is $G$ , the shunt resistance $5$ connected to the galvanometer is

$19 G$

$\frac{G}{19}$

$20 G$

$\frac{G}{20}$

Let the total passing be $I$ .
Thus current passing through galvanometer
$I_{G} = 0.05 I$
Also, current passing through shunt resistance
$I_{s} = I - 0.05 I = 0.95 I$
Using $I_{5} S = I_{G} G$
$∴ \frac{S}{G} = \frac{0.05}{0.95} = \frac{1}{10}$
$\Rightarrow S = \frac{G}{19}$

Q. In a galvanometer 5% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance 5 connected to the galvanometer is

19G

19G​

20G

20G​