In a Frounhofer diffraction experiment, a single slit of width 0.5 mm is illuminated by a monochromatic light of wavelength 600 nm. The diffraction pattern is observed on a screen at a distance of 50 cm from the slit. What will be the linear separation of the first order minima?

Question

In a Frounhofer diffraction experiment, a single slit of width 0.5 mm is illuminated by a monochromatic light of wavelength 600 nm. The diffraction pattern is observed on a screen at a distance of 50 cm from the slit. What will be the linear separation of the first order minima? (A) 1.0 nm (B) 1.1 nm (C) 0.6 mm (D) 1.2 nm

Tardigrade Admin · Accepted Answer

d=0.5 mm λ=600 nm . Width of central maxima =(2 λ D/d) D=50 cm (2 λ D/d)=(2 × 600 × 50 × 10-2 × 10-9/0.5 × 10-3)=1.2 mm

Q. In a Frounhofer diffraction experiment, a single slit of width $0.5 mm$ is illuminated by a monochromatic light of wavelength $600 nm$ . The diffraction pattern is observed on a screen at a distance of $50 c m$ from the slit. What will be the linear separation of the first order minima?

1.0 nm

1.1 nm

0.6 mm

1.2 nm

$d = 0.5 mm$
$λ = 600 nm .$
Width of central maxima $= \frac{2 λ D}{d}$
$D = 50 c m$
$\frac{2 λ D}{d} = \frac{2 \times 600 \times 50 \times 1 0 ^{- 2} \times 1 0 ^{- 9}}{0.5 \times 1 0 ^{- 3}} = 1.2 mm$

Q. In a Frounhofer diffraction experiment, a single slit of width 0.5mm is illuminated by a monochromatic light of wavelength 600nm. The diffraction pattern is observed on a screen at a distance of 50cm from the slit. What will be the linear separation of the first order minima?