In a fluorescent lamp choke 100 V of reverse voltage is produced when the choke current changes uniform from 0.25 A to 0 in a duration of 0.025 ms . The self-inductance of the choke (in mH ) is estimated to be

Question

In a fluorescent lamp choke 100 V of reverse voltage is produced when the choke current changes uniform from 0.25 A to 0 in a duration of 0.025 ms . The self-inductance of the choke (in mH ) is estimated to be (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

100=(L(0.25)/0.025) × 103 ∴ L=100 × 10-4 H =10 mH

Q. In a fluorescent lamp choke $100 V$ of reverse voltage is produced when the choke current changes uniform from $0.25 A$ to $0$ in a duration of $0.025 m s$ . The self-inductance of the choke (in $m H$ ) is estimated to be

$100 = \frac{L ( 0.25 )}{0.025} \times 1 0^{3}$
$∴ L = 100 \times 1 0^{- 4} H$
$= 10 m H$

Q. In a fluorescent lamp choke 100V of reverse voltage is produced when the choke current changes uniform from 0.25A to 0 in a duration of 0.025ms . The self-inductance of the choke (in mH ) is estimated to be

100=0.025L(0.25)​×103 ∴L=100×10−4H =10mH

Q. In a fluorescent lamp choke $100 V$ of reverse voltage is produced when the choke current changes uniform from $0.25 A$ to $0$ in a duration of $0.025 m s$ . The self-inductance of the choke (in $m H$ ) is estimated to be

$100 = \frac{L ( 0.25 )}{0.025} \times 1 0^{3}$
$∴ L = 100 \times 1 0^{- 4} H$
$= 10 m H$