In a fission reaction 92236U arrow 117X+ 117Y+n+n, the binding energy per nucleon of X and Y is 8.5MeV whereas of 236U is 7.6MeV. The total energy liberated will be approximately

Question

In a fission reaction 92236U arrow 117X+ 117Y+n+n, the binding energy per nucleon of X and Y is 8.5MeV whereas of 236U is 7.6MeV. The total energy liberated will be approximately (A) 200KeV (B) 2MeV (C) 200MeV (D) 2000MeV

Tardigrade Admin · Accepted Answer

Δ E=8.5× 234-7.6× 236=195.4MeV≈200MeV

Q. In a fission reaction $_92^{236} U \to_^{117} X +_^{117} Y + n + n,$ the binding energy per nucleon of $X$ and $Y$ is $8.5 M e V$ whereas of $_^{236} U$ is $7.6 M e V .$ The total energy liberated will be approximately

$200 Ke V$

$2 M e V$

$200 M e V$

$2000 M e V$

$Δ E = 8.5 \times 234 - 7.6 \times 236 = 195.4 M e V \approx 200 M e V$

Q. In a fission reaction _92236U→_117X+_117Y+n+n, the binding energy per nucleon of X and Y is 8.5MeV whereas of _236U is 7.6MeV. The total energy liberated will be approximately

200KeV

2MeV

200MeV

2000MeV