In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a distant screen is 0.1°. The spacing between the two slits is

Question

In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a distant screen is 0.1°. The spacing between the two slits is (A) 3.44 × 10-4 m (B) 1.54 × 10-4 m (C) 1.54 × 10-3 m (D) 1.44 × 10-3 m

Tardigrade Admin · Accepted Answer

Angular width of fringe, θ = 0.1° = 0.1 ×(π/180) rad = (3.14/1800)rad ∴ d = (λ/θ) = (600× 10-9/3.14/ 1800) = 3.44 × 10-4 m

Q. In a double slit experiment using light of wavelength $600 nm$ , the angular width of a fringe on a distant screen is $0. 1^{\circ}$ . The spacing between the two slits is

$3.44 \times 1 0^{- 4} m$

$1.54 \times 1 0^{- 4} m$

$1.54 \times 1 0^{- 3} m$

$1.44 \times 1 0^{- 3} m$

Angular width of fringe,
$θ = 0. 1^{\circ} = 0.1 \times \frac{π}{180} r a d$
$= \frac{3.14}{1800} r a d$
$∴ d = \frac{λ}{θ}$
$= \frac{600 \times 1 0 ^{- 9}}{3.14/1800}$
$= 3.44 \times 1 0^{- 4} m$

Q. In a double slit experiment using light of wavelength 600nm, the angular width of a fringe on a distant screen is 0.1∘. The spacing between the two slits is

3.44×10−4m

1.54×10−4m

1.54×10−3m

1.44×10−3m