In a double slit experiment light has a frequency of 6 × 1014 s -1 . The distance between the centres of adjacent bright fringes is 0.75 mm. What is the distance between the slits if the screen is 1.5 m away?

Question

In a double slit experiment light has a frequency of 6 × 1014 s -1 . The distance between the centres of adjacent bright fringes is 0.75 mm. What is the distance between the slits if the screen is 1.5 m away? (A) 10-1 m (B) 10-3 m (C) 10-5 m (D) 1 m

Tardigrade Admin · Accepted Answer

v=6 × 1014 s -1 λ=c / v=(3 × 108/6 × 1014)=5 × 10-7 m β=0.75 mm =0.75 × 10-3 m D =1.5 m β=(λ D / d )=(5 × 10-7 × 1.5/0.75 × 10-3)=10-3 m β=10-3 m

Q. In a double slit experiment light has a frequency of 6 $\times 1 0^{14} s^{- 1} .$ The distance between the centres of adjacent bright fringes is $0.75 mm$ . What is the distance between the slits if the screen is $1.5 m$ away?

$1 0^{- 1} m$

$1 0^{- 3} m$

$1 0^{- 5} m$

$1 m$

$v = 6 \times 1 0^{14} s^{- 1}$
$λ = c / v = \frac{3 \times 1 0 ^{8}}{6 \times 1 0 ^{14}} = 5 \times 1 0^{- 7} m$
$β = 0.75 mm = 0.75 \times 1 0^{- 3} m$
$D = 1.5 m$
$β = \frac{λ D}{d} = \frac{5 \times 1 0 ^{- 7} \times 1.5}{0.75 \times 1 0 ^{- 3}} = 1 0^{- 3} m$
$β = 1 0^{- 3} m$

Q. In a double slit experiment light has a frequency of 6 ×1014s−1. The distance between the centres of adjacent bright fringes is 0.75mm. What is the distance between the slits if the screen is 1.5m away?

10−1m

10−3m

10−5m

1m