In a discharge tube when 200 V potential difference is applied 6.25 × 1018 electrons move from cathode to anode and 3.125 × 1018 singly charged positive ions move from anode to cathode in one second. Then the power of tube (in W) is.

Question

In a discharge tube when 200 V potential difference is applied 6.25 × 1018 electrons move from cathode to anode and 3.125 × 1018 singly charged positive ions move from anode to cathode in one second. Then the power of tube (in W) is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

We use P=Vq=200(6.25 × 1018+3.125 × 1018) × 1.6 × 10-19 =300 watt

Q. In a discharge tube when $200 V$ potential difference is applied $6.25 \times 1 0^{18}$ electrons move from cathode to anode and $3.125 \times 1 0^{18}$ singly charged positive ions move from anode to cathode in one second. Then the power of tube (in $W$ ) is______.

We use $P = V_{q} = 200 (6.25 \times 1 0^{18} + 3.125 \times 1 0^{18}) \times 1.6 \times 1 0^{- 19}$
$= 300$ watt

Q. In a discharge tube when 200V potential difference is applied 6.25×1018 electrons move from cathode to anode and 3.125×1018 singly charged positive ions move from anode to cathode in one second. Then the power of tube (in W) is______.

We use P=Vq​=200(6.25×1018+3.125×1018)×1.6×10−19 =300 watt

Q. In a discharge tube when $200 V$ potential difference is applied $6.25 \times 1 0^{18}$ electrons move from cathode to anode and $3.125 \times 1 0^{18}$ singly charged positive ions move from anode to cathode in one second. Then the power of tube (in $W$ ) is______.

We use $P = V_{q} = 200 (6.25 \times 1 0^{18} + 3.125 \times 1 0^{18}) \times 1.6 \times 1 0^{- 19}$
$= 300$ watt