In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow (YY) and seed colour green (yy) with seed shape round (RR) and seed shape wrinkled (rr), the number of green coloured seeds (yy) among sixteen products of F2 generation will be

Question

In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow (YY) and seed colour green (yy) with seed shape round (RR) and seed shape wrinkled (rr), the number of green coloured seeds (yy) among sixteen products of F2 generation will be (A) 2 (B) 4 (C) 6 (D) 8

Tardigrade Admin · Accepted Answer

In the given dihybrid cross, phenotypes obtained in F2 generation will be as follows Yellow and round seeded plants = 9/16 Yellow and wrinkled seeded plants = 3/16 Green and round seeded plants = 3/16 Green and wrinkled seeded plants = 1/16.

Q. In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow $(YY)$ and seed colour green $(yy)$ with seed shape round $(RR)$ and seed shape wrinkled $(rr)$ , the number of green coloured seeds $(yy)$ among sixteen products of $F_{2}$ generation will be

2

4

6

8

In the given dihybrid cross, phenotypes obtained in $F_{2}$ generation will be as follows Yellow and round seeded plants = $9/16$ Yellow and wrinkled seeded plants $= 3/16$ Green and round seeded plants $= 3/16$ Green and wrinkled seeded plants $= 1/16$ .

Q. In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow (YY) and seed colour green (yy) with seed shape round (RR) and seed shape wrinkled (rr), the number of green coloured seeds (yy) among sixteen products of F2​ generation will be

2

4

6

8

In the given dihybrid cross, phenotypes obtained in F2​ generation will be as follows Yellow and round seeded plants = 9/16 Yellow and wrinkled seeded plants =3/16 Green and round seeded plants =3/16 Green and wrinkled seeded plants =1/16.

Q. In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow $(YY)$ and seed colour green $(yy)$ with seed shape round $(RR)$ and seed shape wrinkled $(rr)$ , the number of green coloured seeds $(yy)$ among sixteen products of $F_{2}$ generation will be

In the given dihybrid cross, phenotypes obtained in $F_{2}$ generation will be as follows Yellow and round seeded plants = $9/16$ Yellow and wrinkled seeded plants $= 3/16$ Green and round seeded plants $= 3/16$ Green and wrinkled seeded plants $= 1/16$ .