In a diatomic molecule the bond distance is 1 × 10-8 cm. Its dipole moment is 1.2 D. What is the fractional electronic charge on each atom?

Question

In a diatomic molecule the bond distance is 1 × 10-8 cm. Its dipole moment is 1.2 D. What is the fractional electronic charge on each atom? (A) 0.50 (B) 1.2 × 10-10 (C) 0.25 (D) 1.2

Tardigrade Admin · Accepted Answer

Partial charge = ( textDipole moment/ textBond distance) = (1.2×10-18 esu cm/1×10-8 cm) = 1.2×10-10 esu Fractional charge =( 1.2×10-10/4.8×10-10) = 0.25 (4.8×10-10 textis a theoretical value of μ.)

Q. In a diatomic molecule the bond distance is $1 \times 1 0^{- 8}$ cm. Its dipole moment is $1.2 D$ . What is the fractional electronic charge on each atom?

$0.50$

$1.2 \times 1 0^{- 10}$

$0.25$

$1.2$

Partial charge $= \frac{Dipole moment}{Bond distance}$
$= \frac{1.2 \times 1 0 ^{- 18} es u c m}{1 \times 1 0 ^{- 8} c m} = 1.2 \times 1 0^{- 10} es u$
Fractional charge $= \frac{1.2 \times 1 0 ^{- 10}}{4.8 \times 1 0 ^{- 10}} = 0.25$
$(4.8 \times 1 0^{- 10} is a theoretical value of μ .)$

Q. In a diatomic molecule the bond distance is 1×10−8 cm. Its dipole moment is 1.2D. What is the fractional electronic charge on each atom?

0.50

1.2×10−10

0.25

1.2