In a concave mirror experiment, an object is placed at a distance x1 from the focus and the image is formed at a distance x2 from the focus. The focal length of the mirror would be

Question

In a concave mirror experiment, an object is placed at a distance x1 from the focus and the image is formed at a distance x2 from the focus. The focal length of the mirror would be (A) x1 x2 (B) √x1 x2 (C) √x1 / x2 (D) (x1+x2/2)

Tardigrade Admin · Accepted Answer

According to Newton's formula f1 f2=x1 x2. But f1=f2=f ∴ f2=x1 x2 or f=√x1 x2

Q. In a concave mirror experiment, an object is placed at a distance $x_{1}$ from the focus and the image is formed at a distance $x_{2}$ from the focus. The focal length of the mirror would be

$x_{1} x_{2}$

$x_{1} x_{2}$

$x_{1} / x_{2}$

$\frac{x _{1} + x _{2}}{2}$

According to Newton's formula
$f_{1} f_{2} = x_{1} x_{2}$ .
But $f_{1} = f_{2} = f$
$∴ f^{2} = x_{1} x_{2}$
or $f = x_{1} x_{2}$

Q. In a concave mirror experiment, an object is placed at a distance x1​ from the focus and the image is formed at a distance x2​ from the focus. The focal length of the mirror would be

x1​x2​

x1​x2​​

x1​/x2​​

2x1​+x2​​

According to Newton's formula f1​f2​=x1​x2​. But f1​=f2​=f ∴f2=x1​x2​ or f=x1​x2​​

Q. In a concave mirror experiment, an object is placed at a distance $x_{1}$ from the focus and the image is formed at a distance $x_{2}$ from the focus. The focal length of the mirror would be

$x_{1} x_{2}$

$x_{1} x_{2}$

$x_{1} / x_{2}$

$\frac{x _{1} + x _{2}}{2}$

According to Newton's formula
$f_{1} f_{2} = x_{1} x_{2}$ .
But $f_{1} = f_{2} = f$
$∴ f^{2} = x_{1} x_{2}$
or $f = x_{1} x_{2}$