In a compound electrophilic substitution has occured. The substituent- E are methyl, - CH 2 Cl ,- CCl 3 and - CHCl 2. The correct increasing order towards electrophilic substitution is

Question

In a compound <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/2ec3f9546cb8842cd22e39085c234568-.png" /> electrophilic substitution has occured. The substituent- E are methyl, - CH 2 Cl ,- CCl 3 and - CHCl 2. The correct increasing order towards electrophilic substitution is (A) - CH 3<- CH 2 Cl <- CHCl 2<- CCl 3 (B) - CH 3<- CHCl 2<- CH 2 Cl <- CCl 3 (C) - CCl 3<- CH 2 Cl <- CHCl 2<- CH 3 (D) - CCl 3<- CHCl 2<- CH 2 Cl <- CH 3

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Chlorine atoms are strongly negative (show -I effect). They deactivate the ring towards electrophilic reaction.

Q. In a compound electrophilic substitution has occured. The substituent- $E$ are methyl, $- C H_{2} Cl, - CC l_{3}$ and - CHCl $_{2}$ . The correct increasing order towards electrophilic substitution is

$- C H_{3} < - C H_{2} Cl < - C H C l_{2} < - CC l_{3}$

$- C H_{3} < - C H C l_{2} < - C H_{2} Cl < - CC l_{3}$

$- CC l_{3} < - C H_{2} Cl < - C H C l_{2} < - C H_{3}$

$- CC l_{3} < - C H C l_{2} < - C H_{2} Cl < - C H_{3}$

Chlorine atoms are strongly negative (show -I effect). They deactivate the ring towards electrophilic reaction.

Q. In a compound electrophilic substitution has occured. The substituent- E are methyl, −CH2​Cl,−CCl3​ and - CHCl 2​. The correct increasing order towards electrophilic substitution is

−CH3​<−CH2​Cl<−CHCl2​<−CCl3​

−CH3​<−CHCl2​<−CH2​Cl<−CCl3​

−CCl3​<−CH2​Cl<−CHCl2​<−CH3​

−CCl3​<−CHCl2​<−CH2​Cl<−CH3​

Chlorine atoms are strongly negative (show -I effect). They deactivate the ring towards electrophilic reaction.

Q. In a compound electrophilic substitution has occured. The substituent- $E$ are methyl, $- C H_{2} Cl, - CC l_{3}$ and - CHCl $_{2}$ . The correct increasing order towards electrophilic substitution is

$- C H_{3} < - C H_{2} Cl < - C H C l_{2} < - CC l_{3}$

$- C H_{3} < - C H C l_{2} < - C H_{2} Cl < - CC l_{3}$

$- CC l_{3} < - C H_{2} Cl < - C H C l_{2} < - C H_{3}$

$- CC l_{3} < - C H C l_{2} < - C H_{2} Cl < - C H_{3}$