In a common emitter transistor amplifier an increase of 50 μ A in the base current causes an increase of 1 mA in the collector current. The change in emitter current is

Question

In a common emitter transistor amplifier an increase of 50 μ A in the base current causes an increase of 1 mA in the collector current. The change in emitter current is (A) 1050 mA (B) 1050 μ A (C) 5025 mA (D) 5025 μ A

Tardigrade Admin · Accepted Answer

The change in emitter current is Δ IE = Δ IB + Δ IC = 50 × 10-6 + 1 × 10-3 = 1050 × 10-6 A = 1050 μ A

Q. In a common emitter transistor amplifier an increase of $50 μ A$ in the base current causes an increase of $1 m A$ in the collector current. The change in emitter current is

$1050 m A$

$1050 μ A$

$5025 m A$

$5025 μ A$

The change in emitter current is
$Δ I_{E} = Δ I_{B} + Δ I_{C}$
$= 50 \times 1 0^{- 6} + 1 \times 1 0^{- 3}$
$= 1050 \times 1 0^{- 6} A$
$= 1050 μ A$

Q. In a common emitter transistor amplifier an increase of 50μA in the base current causes an increase of 1mA in the collector current. The change in emitter current is

1050mA

1050μA

5025mA

5025μA