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Q. In a common emitter transistor amplifier an increase of $50 \,\mu A$ in the base current causes an increase of $1 \,mA$ in the collector current. The change in emitter current is

JIPMERJIPMER 2014Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

The change in emitter current is
$\Delta I_E = \Delta I_B + \Delta I_C$
$ = 50 \times 10^{-6} + 1 \times 10^{-3}$
$= 1050 \times 10^{-6} A$
$ = 1050\, \mu A$