Question

In a coil of self-inductance $5$ henry, the rate of change of current is $2$ ampere per second. The e.m.f. induced in the coil, is

• A. 10 V
• B. - 10 V
• C. 5 V
• D. - 5 V

Answer 1

Answer: (B)

Given : Inductance of the coil $(L)=5H$ and rate of change of current $\left(\frac{dI}{dt}\right)=2$ A/sec. The induced e.m.f.
$=-L\left(\frac{dI}{dt}\right)=-5\times 2=-10V$