In a coil of resistance 20 Ω, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil is :-

Question

In a coil of resistance 20 Ω, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil is :- (A) 6 Wb (B) 4 Wb (C) 8 Wb (D) 2 Wb

Tardigrade Admin · Accepted Answer

Charge flown =(Δ φ/ R ) Area of I - t curve =( text change in flux / R ) ⇒ change in flux =(1/2) × 2 × 0.1 × 20=2 wb

Q. In a coil of resistance $20 Ω$ , the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil is :-

6 Wb

4 Wb

8 Wb

2 Wb

Charge flown $= \frac{Δ ϕ}{R}$
Area of $I - t$ curve $= \frac{change in flux}{R}$
$\Rightarrow$ change in flux $= \frac{1}{2} \times 2 \times 0.1 \times 20 = 2 w b$

Q. In a coil of resistance 20Ω, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil is :-