In a coil of area 10cm2 and 10 turns, magnetic field is directed perpendicular to the plane and is changing at a rate of 104Ts- 1 . The resistance of the coil is 20 Ω . The current in the coil will be

Question

In a coil of area 10cm2 and 10 turns, magnetic field is directed perpendicular to the plane and is changing at a rate of 104Ts- 1 . The resistance of the coil is 20 Ω . The current in the coil will be (A) 0.5 A (B) 5 A (C) 50 A (D) 5× 108 A

Tardigrade Admin · Accepted Answer

Induced current is, i=(1/R)(N (dÏ/dt))=(1/R)(NA (dB/dt)) i=(1/20)(10) (10 × (10)- 4)((10)4)=5 A i=5A

Q. In a coil of area $10 c m^{2}$ and $10$ turns, magnetic field is directed perpendicular to the plane and is changing at a rate of $1 0^{4} T s^{- 1}$ . The resistance of the coil is $20 Ω$ . The current in the coil will be

$0.5 A$

$5 A$

$50 A$

$5 \times 1 0^{8} A$

Induced current is,
$i = \frac{1}{R} (N \frac{d ϕ}{d t}) = \frac{1}{R} (N A \frac{d B}{d t})$
$i = \frac{1}{20} (10) (10 \times (10)^{- 4}) ((10)^{4}) = 5 A$
$i = 5 A$

Q. In a coil of area 10cm2 and 10 turns, magnetic field is directed perpendicular to the plane and is changing at a rate of 104Ts−1 . The resistance of the coil is 20Ω . The current in the coil will be

0.5A

5A

50A

5×108A