In a closed system, A ( s ) leftharpoons 2 B ( g )+3 C ( g ), if partial pressure of C is doubled, then partial pressure of B will be

Question

In a closed system, A ( s ) leftharpoons 2 B ( g )+3 C ( g ), if partial pressure of C is doubled, then partial pressure of B will be (A) 2 √2 times the original value (B) (1/2) times the original value (C) 2 times the original value (D) (1/2 √2) times the original value

Tardigrade Admin · Accepted Answer

Kp=pB13 × pC13 Again, Kp=pB22 ×(2 pC1)3 ∴ pB12 × pC13=PB22 × 8 pC13 ∴ (pB12/8)=pB22, (pB1/2 √2)=pB2

Q. In a closed system, $A (s) ⇌ 2 B (g) + 3 C (g)$ , if partial pressure of $C$ is doubled, then partial pressure of $B$ will be

$22$ times the original value

$\frac{1}{2}$ times the original value

2 times the original value

$\frac{1}{2 2}$ times the original value

$K_{p} = p_{B_{1}}^{3} \times p_{C_{1}}^{3}$
Again, $K_{p} = p_{B_{2}}^{2} \times (2 p_{C_{1}})^{3}$
$∴ p_{B_{1}}^{2} \times p_{C_{1}}^{3} = P_{B_{2}}^{2} \times 8 p_{C_{1}}^{3}$
$∴ \frac{p _{B_{1}}^{2}}{8} = p_{B_{2}}^{2}, \frac{p _{B_{1}}}{2 2} = p_{B_{2}}$

Q. In a closed system, A(s)⇌2B(g)+3C(g), if partial pressure of C is doubled, then partial pressure of B will be

22​ times the original value

21​ times the original value