In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true: -

Question

In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true: - (A) Δ E = W ≠ 0 , q = 0 (B) Δ E = W =q ≠ 0 (C) Δ E =0, W = q ≠ 0 (D) W = 0 Δ E = q ≠ 0

Tardigrade Admin · Accepted Answer

In closed insulated container a liquid is stirred with a paddle to increase the temperature, therefore it behaves as adiabatic process, so, for it

q = 0

. Hence, from first law of thermodynamics

Δ E = q + W i f q = 0

∴ Δ E = W

but not equal to zero.

Q. In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true : -

$Δ E = W \neq = 0, q = 0$

$Δ E = W = q \neq = 0$

$Δ E = 0, W = q \neq = 0$

$W = 0 Δ E = q \neq = 0$

In closed insulated container a liquid is stirred with a paddle to increase the temperature, therefore it behaves as adiabatic process, so, for it $q = 0$ . Hence, from first law of thermodynamics
$Δ E = q + W i f q = 0$
$∴ Δ E = W$ but not equal to zero.

Q. In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true : -

ΔE=W=0,q=0

ΔE=W=q=0

ΔE=0,W=q=0

W=0ΔE=q=0

In closed insulated container a liquid is stirred with a paddle to increase the temperature, therefore it behaves as adiabatic process, so, for it q=0. Hence, from first law of thermodynamics ΔE=q+Wifq=0 ∴ΔE=W but not equal to zero.

$Δ E = W \neq = 0, q = 0$

$Δ E = W = q \neq = 0$

$Δ E = 0, W = q \neq = 0$

$W = 0 Δ E = q \neq = 0$

In closed insulated container a liquid is stirred with a paddle to increase the temperature, therefore it behaves as adiabatic process, so, for it $q = 0$ . Hence, from first law of thermodynamics
$Δ E = q + W i f q = 0$
$∴ Δ E = W$ but not equal to zero.