In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is :In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is :

Question

In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is :In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is : (A) (2/3) (B) (1/6) (C) (1/3) (D) (5/6)

Tardigrade Admin · Accepted Answer

A arrow opted NCC B arrow opted NSS ∴ P (nither A nor B) = (10/60) = z (1/6)

$\frac{2}{3}$

$\frac{1}{6}$

$\frac{1}{3}$

$\frac{5}{6}$

$A \to$ opted NCC
$B \to$ opted NSS
$∴$ P (nither A nor B) = $\frac{10}{60} = z \frac{1}{6}$

32​

61​

31​

65​

A→opted NCC B→opted NSS ∴P (nither A nor B) = 6010​=z61​

$\frac{2}{3}$

$\frac{1}{6}$

$\frac{1}{3}$

$\frac{5}{6}$

$A \to$ opted NCC
$B \to$ opted NSS
$∴$ P (nither A nor B) = $\frac{10}{60} = z \frac{1}{6}$