In a class of 60 boys and 20 girls, half of the boys and half of the girls know cricket, then the probability of the event that a person selected from the class is either a boy or a girl who knows cricket is

Question

In a class of 60 boys and 20 girls, half of the boys and half of the girls know cricket, then the probability of the event that a person selected from the class is either a boy or a girl who knows cricket is (A) (1/2) (B) (3/8) (C) (5/8) (D) (7/8)

Tardigrade Admin · Accepted Answer

Step - 1: Find probability of boys and girls knowing cricket
Total number of student

= 60 + 20 = 80

Probability of selecting boys

= \frac{60}{80} = \frac{3}{4}

Number of girls in class

= 20

Numbers of girls knowing cricket

= 10

Probability that selected one is girl knowing cricket

= \frac{10}{80} = \frac{1}{8}

Step - 2: Find probability
Probability of either boy or girls knowing cricket is
Total probability

= \frac{3}{4} + \frac{1}{8}

= \frac{6 + 1}{8} = \frac{7}{8}

Hence, the answer is

\frac{7}{8}

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Q. In a class of 60 boys and 20 girls, half of the boys and half of the girls know cricket, then the probability of the event that a person selected from the class is either a boy or a girl who knows cricket is

$\frac{1}{2}$

$\frac{3}{8}$

$\frac{5}{8}$

$\frac{7}{8}$

Q. In a class of 60 boys and 20 girls, half of the boys and half of the girls know cricket, then the probability of the event that a person selected from the class is either a boy or a girl who knows cricket is

21​

83​

85​

87​

$\frac{1}{2}$

$\frac{3}{8}$

$\frac{5}{8}$

$\frac{7}{8}$