In a circular motion of a particle, the tangential acceleration of the particle is given by at=9 m s- 2 . The radius of the circle is 4 m . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of 45° with the radial acceleration is

Question

In a circular motion of a particle, the tangential acceleration of the particle is given by at=9 m s- 2 . The radius of the circle is 4 m . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of 45° with the radial acceleration is (A) (1/3)s (B) (2/3)s (C) (5/3)s (D) (4/3)s

Tardigrade Admin · Accepted Answer

At 45° , at=ar=9 ( textv2/ textr) = ( textv2/4) = 9 v=6ms- 1 6=0+9t t=(2/3)s .

$\frac{1}{3} s$

$\frac{2}{3} s$

$\frac{5}{3} s$

$\frac{4}{3} s$

At $4 5^{\circ}$ , $a_{t} = a_{r} = 9$
$\frac{v ^{2}}{r} = \frac{v ^{2}}{4} = 9$
$v = 6 m s^{- 1}$
$6 = 0 + 9 t$
$t = \frac{2}{3} s$ .

Q. In a circular motion of a particle, the tangential acceleration of the particle is given by at​=9ms−2 . The radius of the circle is 4m . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of 45∘ with the radial acceleration is

31​s

32​s

35​s

34​s

At 45∘ , at​=ar​=9 rv2​=4v2​=9 v=6ms−1 6=0+9t t=32​s .

$\frac{1}{3} s$

$\frac{2}{3} s$

$\frac{5}{3} s$

$\frac{4}{3} s$

At $4 5^{\circ}$ , $a_{t} = a_{r} = 9$
$\frac{v ^{2}}{r} = \frac{v ^{2}}{4} = 9$
$v = 6 m s^{- 1}$
$6 = 0 + 9 t$
$t = \frac{2}{3} s$ .