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  4. In a circular motion of a particle, the tangential acceleration of the particle is given by at=9 m s- 2 . The radius of the circle is 4 m . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of 45° with the radial acceleration is

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Q. In a circular motion of a particle, the tangential acceleration of the particle is given by $a_{t}=9 \, m \, s^{- 2}$ . The radius of the circle is $4 \, m$ . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of $45^\circ $ with the radial acceleration is

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

At $45^\circ $ , $a_{t}=a_{r}=9$
$\frac{\text{v}^{2}}{\text{r}} = \frac{\text{v}^{2}}{4} = 9$
$v=6ms^{- 1}$
$6=0+9t$
$t=\frac{2}{3}s$ .