In a chemical equilibrium the rate constant of backward reaction is 3.2 × 10-2 and the equilibrium constant is 2-5. The rate constant of forward reaction is

Question

In a chemical equilibrium the rate constant of backward reaction is 3.2 × 10-2 and the equilibrium constant is 2-5. The rate constant of forward reaction is (A) 1 × 10-3 (B) 2 × 10-2 (C) 8 × 10-2 (D) 4 × 10-2

Tardigrade Admin · Accepted Answer

In a chemical equilibrium Equilibrium constant, K=( textRate constant of forward reaction, Kf/ textRate constant of backward reaction, Kb) ∴ Kf=Kb× K =3.2×10-2×2-5 =(3.2×10-2/32)=1×10-3

Q. In a chemical equilibrium the rate constant of backward reaction is $3.2 \times 1 0^{- 2}$ and the equilibrium constant is $2^{- 5}$ . The rate constant of forward reaction is

$1 \times 1 0^{- 3}$

$2 \times 1 0^{- 2}$

$8 \times 1 0^{- 2}$

$4 \times 1 0^{- 2}$

In a chemical equilibrium
Equilibrium constant,
$K = \frac{Rate constant of forward reaction , K _{f}}{Rate constant of backward reaction , K _{b}}$
$∴ K_{f} = K_{b} \times K$
$= 3.2 \times 1 0^{- 2} \times 2^{- 5}$
$= \frac{3.2 \times 1 0 ^{- 2}}{32} = 1 \times 1 0^{- 3}$

Q. In a chemical equilibrium the rate constant of backward reaction is 3.2×10−2 and the equilibrium constant is 2−5. The rate constant of forward reaction is

1×10−3

2×10−2

8×10−2

4×10−2