In a certain thermodynamical process, the pressure of a gas depends on its volume as kv3 . The work done when the temperature changes from 100° C to 300° C will be nR , where n denotes number of moles of a gas.

Question

In a certain thermodynamical process, the pressure of a gas depends on its volume as kv3 . The work done when the temperature changes from 100° C to 300° C will be nR , where n denotes number of moles of a gas. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P=kv3 pv- 3=k x=-3 w=(n R (T1 - T2)/x - 1) =(n R (. 100 - 300 .)/- 3 - 1) =(n R (. - 200 .)/- 4) =50nR

Q. In a certain thermodynamical process, the pressure of a gas depends on its volume as $k v^{3}$ . The work done when the temperature changes from $10 0^{\circ} C$ to $30 0^{\circ} C$ will be $n R$ , where $n$ denotes number of moles of a gas.

$P = k v^{3}$
$p v^{- 3} = k$
$x = - 3$
$w = \frac{n R ( T _{1} - T _{2} )}{x - 1}$
$= \frac{n R ( 100 - 300 )}{- 3 - 1}$
$= \frac{n R ( - 200 )}{- 4}$
$= 50 n R$

Q. In a certain thermodynamical process, the pressure of a gas depends on its volume as kv3 . The work done when the temperature changes from 100∘C to 300∘C will be nR , where n denotes number of moles of a gas.

P=kv3 pv−3=k x=−3 w=x−1nR(T1​−T2​)​ =−3−1nR(100−300)​ =−4nR(−200)​ =50nR

Q. In a certain thermodynamical process, the pressure of a gas depends on its volume as $k v^{3}$ . The work done when the temperature changes from $10 0^{\circ} C$ to $30 0^{\circ} C$ will be $n R$ , where $n$ denotes number of moles of a gas.

$P = k v^{3}$
$p v^{- 3} = k$
$x = - 3$
$w = \frac{n R ( T _{1} - T _{2} )}{x - 1}$
$= \frac{n R ( 100 - 300 )}{- 3 - 1}$
$= \frac{n R ( - 200 )}{- 4}$
$= 50 n R$