In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V=8 x2+2, where x is the x-coordinate of a point in space. The magnitude of electric field at a point (-4,0) is

Question

In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V=8 x2+2, where x is the x-coordinate of a point in space. The magnitude of electric field at a point (-4,0) is (A) - 16 V/m (B) 16 V/m (C) - 64 V/m (D) 64 V/m

Tardigrade Admin · Accepted Answer

V=8 x2+2 Ex=(-d V/d x)=-16 x x=-4 Ex=64 V / m

Q. In a certain region of space, variation of potential with distance from origin as we move along $x$ -axis is given by $V = 8 x^{2} + 2$ , where $x$ is the $x$ -coordinate of a point in space. The magnitude of electric field at a point $(- 4, 0)$ is

- 16 V/m

16 V/m

- 64 V/m

64 V/m

$V = 8 x^{2} + 2$
$E_{x} = \frac{- d V}{d x} = - 16 x$
$x = - 4$
$E_{x} = 64 V / m$

Q. In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V=8x2+2, where x is the x-coordinate of a point in space. The magnitude of electric field at a point (−4,0) is