In a carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance 1.12× 10-10m . The distance of the centre of mass, from the carbon atom is :

Question

In a carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance 1.12× 10-10m . The distance of the centre of mass, from the carbon atom is : (A)  o.64× 10-10m  (B)  o.56× 10-10m  (C)  o.51× 10-10m  (D)  o.48× 10-10m

Tardigrade Admin · Accepted Answer

Key Idea: The cartesian co-ordinate of the centre of mass is

\frac{i Σ m _{i} x _{i}}{Σ m _{i}}

Let the distance of the centre of mass from the carbon atom be r. The mass of carbon,

m_{1} = 12 am u

The mass of oxygen,

m_{2} = 16 am u

From definition of centre of mass

x_{c m} = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}}

= \frac{( 12 am u ) \times 0 + ( 16 am u ) \times r}{12 am u + 16 am u}

= \frac{16}{28} r = \frac{16}{28} \times 1.12 \times 10^{- 10} m

= 0.64 \times 10^{- 10} m

Q. In a carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance $1.12 \times 10^{- 10} m$ . The distance of the centre of mass, from the carbon atom is :

$o .64 \times 10^{- 10} m$

$o .56 \times 10^{- 10} m$

$o .51 \times 10^{- 10} m$

$o .48 \times 10^{- 10} m$

Q. In a carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance 1.12×10−10m . The distance of the centre of mass, from the carbon atom is :

o.64×10−10m

o.56×10−10m

o.51×10−10m

o.48×10−10m

Q. In a carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance $1.12 \times 10^{- 10} m$ . The distance of the centre of mass, from the carbon atom is :

$o .64 \times 10^{- 10} m$

$o .56 \times 10^{- 10} m$

$o .51 \times 10^{- 10} m$

$o .48 \times 10^{- 10} m$