In a capillary tube having area of cross-section A , the water rises to a height h . If the cross-sectional area is reduced to (A/9) , the rise of water in the capillary tube is

Question

In a capillary tube having area of cross-section A , the water rises to a height h . If the cross-sectional area is reduced to (A/9) , the rise of water in the capillary tube is (A) 4h (B) 3h (C) 2h (D) h

Tardigrade Admin · Accepted Answer

A1 = π r12 A2 = π r22 (π r12/9) = π r22 (r12/r22) = 9 ⇒ (r1/r2) = 3 r h = constant r1 h1 = r2 h2 (r1/r2) = (h2/h1) 3 = (h2/h1) = (h2/h1) h2 = 3 h1 = 3 h

Q. In a capillary tube having area of cross-section $A$ , the water rises to a height $h$ . If the cross-sectional area is reduced to $\frac{A}{9}$ , the rise of water in the capillary tube is

$4 h$

$3 h$

$2 h$

$h$

Q. In a capillary tube having area of cross-section A , the water rises to a height h . If the cross-sectional area is reduced to 9A​ , the rise of water in the capillary tube is

4h

3h

2h

h

A1​=πr12​ A2​=πr22​ 9πr12​​=πr22​ r22​r12​​=9⇒r2​r1​​=3 rh= constant r1​h1​=r2​h2​ r2​r1​​=h1​h2​​ 3=h1​h2​​=h1​h2​​ h2​=3h1​=3h

Q. In a capillary tube having area of cross-section $A$ , the water rises to a height $h$ . If the cross-sectional area is reduced to $\frac{A}{9}$ , the rise of water in the capillary tube is

$4 h$

$3 h$

$2 h$

$h$