In a capillary tube experiment, a vertical, 30 cm long capillary tube is dipped in water. The water rises upto a height of 10 cm due to capillary action If this experiment is conducted in a freely falling elevator, the length of the water column becomes :

Question

In a capillary tube experiment, a vertical, 30 cm long capillary tube is dipped in water. The water rises upto a height of 10 cm due to capillary action If this experiment is conducted in a freely falling elevator, the length of the water column becomes : (A) 10 cm (B) 20 cm (C) 30 cm (D) zero

Tardigrade Admin · Accepted Answer

Height of liquid in capillary T=(rhdg/2) h=(2T/rdg) In freely falling elevator acceleration will be zero. ∴ h=∞ i.e., the water will rise upto maximum available height hence 30cm.

Q. In a capillary tube experiment, a vertical, 30 cm long capillary tube is dipped in water. The water rises upto a height of 10 cm due to capillary action If this experiment is conducted in a freely falling elevator, the length of the water column becomes :

10 cm

20 cm

30 cm

zero

Height of liquid in capillary $T = \frac{r h d g}{2}$ $h = \frac{2 T}{r d g}$ In freely falling elevator acceleration will be zero. $∴$ $h = \infty$ i.e., the water will rise upto maximum available height hence 30cm.

Q. In a capillary tube experiment, a vertical, 30 cm long capillary tube is dipped in water. The water rises upto a height of 10 cm due to capillary action If this experiment is conducted in a freely falling elevator, the length of the water column becomes :

10 cm

20 cm

30 cm

zero

Height of liquid in capillary T=2rhdg​ h=rdg2T​ In freely falling elevator acceleration will be zero. ∴ h=∞ i.e., the water will rise upto maximum available height hence 30cm.

Height of liquid in capillary $T = \frac{r h d g}{2}$ $h = \frac{2 T}{r d g}$ In freely falling elevator acceleration will be zero. $∴$ $h = \infty$ i.e., the water will rise upto maximum available height hence 30cm.