In a Bohr model of an atom, when an electron jumps from n = 3 to n = 1, how much energy will be emitted?

Question

In a Bohr model of an atom, when an electron jumps from n = 3 to n = 1, how much energy will be emitted? (A) 2.15 × 10-11 ergs (B) 2.389 × 10-12 j (C) 0.239 × 10-10 ergs (D) 0.1936× 10-10 ergs

Tardigrade Admin · Accepted Answer

Δ E =(- R H / n f 2)-(- R H / n i 2) n i n f stands for initial and final orbit respectively R H = rydrberg's constant =2.18 × 10-18 beginarrayl Δ E =(-2.18 × 10-18 / 32)-(-2.18 × 10-18 / 12) Δ E =2.18 × 10-18(1 / 32-1) Δ E =1.94 × 10-10 J endarray

Q. In a Bohr model of an atom, when an electron jumps from n = 3 to n = 1, how much energy will be emitted?

$2.15 \times 1 0^{- 11}$ ergs

$2.389 \times 1 0^{- 12} j$

$0.239 \times 1 0^{- 10}$ ergs

$0.1936 \times 1 0^{- 10}$ ergs

Q. In a Bohr model of an atom, when an electron jumps from n = 3 to n = 1, how much energy will be emitted?

2.15×10−11 ergs

2.389×10−12j

0.239×10−10 ergs

0.1936×10−10 ergs

ΔE=(−RH​/nf2​)−(−RH​/ni2​) ni​&nf​ stands for initial and final orbit respectively RH​= rydrberg's constant =2.18×10−18 ΔE=(−2.18×10−18/32)−(−2.18×10−18/12)ΔE=2.18×10−18(1/32−1)ΔE=1.94×10−10J​

$2.15 \times 1 0^{- 11}$ ergs

$2.389 \times 1 0^{- 12} j$

$0.239 \times 1 0^{- 10}$ ergs

$0.1936 \times 1 0^{- 10}$ ergs