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Q.
In a Bohr model of an atom, when an electron jumps from n = 3 to n = 1, how much energy will be emitted?
AIPMTAIPMT 1996Structure of Atom
Solution:
$
\Delta E =\left(- R _{ H } / n _{ f }^{2}\right)-\left(- R _{ H } / n _{ i }^{2}\right)
$
$n _{ i } \& n _{ f }$ stands for initial and final orbit respectively
$R _{ H }=$ rydrberg's constant $=2.18 \times 10^{-18}$
$
\begin{array}{l}
\Delta E =\left(-2.18 \times 10^{-18} / 3^{2}\right)-\left(-2.18 \times 10^{-18} / 1^{2}\right) \\
\Delta E =2.18 \times 10^{-18}\left(1 / 3^{2}-1\right) \\
\Delta E =1.94 \times 10^{-10} J
\end{array}
$