In a 10 litre box 2.5 mole hydroiodic acid is taken. After equilibrium 2HIleftharpoons H2+I2 the concentration of HI is found to be 0.1 textmol textL- 1 . The concentration of [H2] at equilibrium in mol L- 1 , is

Question

In a 10 litre box 2.5 mole hydroiodic acid is taken. After equilibrium 2HIleftharpoons H2+I2 the concentration of HI is found to be 0.1 textmol textL- 1 . The concentration of [H2] at equilibrium in mol L- 1 , is (A) 2.4 (B) 0.15 (C) 1.5 (D) 7.5× 10- 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-qpk7aeuszgkz.png" /> 0.25-2 at equilibrium 0.25-2x=0.1 x=7.5× 10- 2

Q. In a $10 l i t re$ box $2.5 m o l e$ hydroiodic acid is taken. After equilibrium $2 H I ⇌ H_{2} + I_{2}$ the concentration of $H I$ is found to be $0.1 mol L^{- 1}$ . The concentration of $[H_{2}]$ at equilibrium in mol $L^{- 1}$ , is

$2.4$

$0.15$

$1.5$

$7.5 \times 1 0^{- 2}$

$0.25 - 2$ at equilibrium

$0.25 - 2 x = 0.1$

$x = 7.5 \times 1 0^{- 2}$

Q. In a 10litre box 2.5mole hydroiodic acid is taken. After equilibrium 2HI⇌H2​+I2​ the concentration of HI is found to be 0.1molL−1 . The concentration of [H2​] at equilibrium in mol L−1 , is

2.4

0.15

1.5

7.5×10−2