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Q. In a $10 \, litre$ box $2.5 \, mole$ hydroiodic acid is taken. After equilibrium $2HI\rightleftharpoons H_{2}+I_{2}$ the concentration of $HI$ is found to be $0.1 \, \text{mol} \, \text{L}^{- 1}$ . The concentration of $\left[H_{2}\right]$ at equilibrium in mol $L^{- 1}$ , is

NTA AbhyasNTA Abhyas 2020Equilibrium

Solution:

Solution

$0.25-2$ at equilibrium

$0.25-2x=0.1$

$x=7.5\times 10^{- 2}$